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Foster named AFC Offensive Player of the Week

Posted Oct 5, 2011

Texans running back Arian Foster has been named the Week 4 AFC Offensive Player of the Week, the second time in his career to win the award.


Texans running back Arian Foster has been named the Week 4 AFC Offensive Player of the Week.

Foster ran for 155 yards on 30 carries (5.2 average) with a touchdown in the Texans’ 17-10 victory over the Pittsburgh Steelers. His rushing total was the highest in the AFC in Week 4 and the most by any player against Pittsburgh since 2003. Foster scored the game-winning touchdown on a 42-yard run in the fourth quarter, shedding tackles from Pro Bowlers LaMarr Woodley and Troy Polamalu along the way.

After missing two of the first three games with a hamstring injury, Foster became the first player in the NFL this season to average at least five yards with 30 or more carries in a game. The 2010 NFL rushing leader and first-team All-Pro posted his 10th-career 100-yard rushing game and first of this season.

This is the second time Foster has been named AFC Offensive Player of the Week. He also won the award in Week 1 of last season, when he ran for a career-high 231 yards and three touchdowns against the Indianapolis Colts.

Foster is a finalist for the FedEx NFL Ground Player of the Week award, which is determined by fan votes. Click here for more information.

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